3.55 \(\int \frac {x^2}{\sinh ^{-1}(a x)^2} \, dx\)

Optimal. Leaf size=54 \[ -\frac {\text {Shi}\left (\sinh ^{-1}(a x)\right )}{4 a^3}+\frac {3 \text {Shi}\left (3 \sinh ^{-1}(a x)\right )}{4 a^3}-\frac {x^2 \sqrt {a^2 x^2+1}}{a \sinh ^{-1}(a x)} \]

[Out]

-1/4*Shi(arcsinh(a*x))/a^3+3/4*Shi(3*arcsinh(a*x))/a^3-x^2*(a^2*x^2+1)^(1/2)/a/arcsinh(a*x)

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Rubi [A]  time = 0.05, antiderivative size = 54, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {5665, 3298} \[ -\frac {\text {Shi}\left (\sinh ^{-1}(a x)\right )}{4 a^3}+\frac {3 \text {Shi}\left (3 \sinh ^{-1}(a x)\right )}{4 a^3}-\frac {x^2 \sqrt {a^2 x^2+1}}{a \sinh ^{-1}(a x)} \]

Antiderivative was successfully verified.

[In]

Int[x^2/ArcSinh[a*x]^2,x]

[Out]

-((x^2*Sqrt[1 + a^2*x^2])/(a*ArcSinh[a*x])) - SinhIntegral[ArcSinh[a*x]]/(4*a^3) + (3*SinhIntegral[3*ArcSinh[a
*x]])/(4*a^3)

Rule 3298

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(I*SinhIntegral[(c*f*fz)
/d + f*fz*x])/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*e - c*f*fz*I, 0]

Rule 5665

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[(x^m*Sqrt[1 + c^2*x^2]*(a + b*ArcSi
nh[c*x])^(n + 1))/(b*c*(n + 1)), x] - Dist[1/(b*c^(m + 1)*(n + 1)), Subst[Int[ExpandTrigReduce[(a + b*x)^(n +
1), Sinh[x]^(m - 1)*(m + (m + 1)*Sinh[x]^2), x], x], x, ArcSinh[c*x]], x] /; FreeQ[{a, b, c}, x] && IGtQ[m, 0]
&& GeQ[n, -2] && LtQ[n, -1]

Rubi steps

\begin {align*} \int \frac {x^2}{\sinh ^{-1}(a x)^2} \, dx &=-\frac {x^2 \sqrt {1+a^2 x^2}}{a \sinh ^{-1}(a x)}+\frac {\operatorname {Subst}\left (\int \left (-\frac {\sinh (x)}{4 x}+\frac {3 \sinh (3 x)}{4 x}\right ) \, dx,x,\sinh ^{-1}(a x)\right )}{a^3}\\ &=-\frac {x^2 \sqrt {1+a^2 x^2}}{a \sinh ^{-1}(a x)}-\frac {\operatorname {Subst}\left (\int \frac {\sinh (x)}{x} \, dx,x,\sinh ^{-1}(a x)\right )}{4 a^3}+\frac {3 \operatorname {Subst}\left (\int \frac {\sinh (3 x)}{x} \, dx,x,\sinh ^{-1}(a x)\right )}{4 a^3}\\ &=-\frac {x^2 \sqrt {1+a^2 x^2}}{a \sinh ^{-1}(a x)}-\frac {\text {Shi}\left (\sinh ^{-1}(a x)\right )}{4 a^3}+\frac {3 \text {Shi}\left (3 \sinh ^{-1}(a x)\right )}{4 a^3}\\ \end {align*}

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Mathematica [A]  time = 0.17, size = 49, normalized size = 0.91 \[ -\frac {\frac {4 a^2 x^2 \sqrt {a^2 x^2+1}}{\sinh ^{-1}(a x)}+\text {Shi}\left (\sinh ^{-1}(a x)\right )-3 \text {Shi}\left (3 \sinh ^{-1}(a x)\right )}{4 a^3} \]

Antiderivative was successfully verified.

[In]

Integrate[x^2/ArcSinh[a*x]^2,x]

[Out]

-1/4*((4*a^2*x^2*Sqrt[1 + a^2*x^2])/ArcSinh[a*x] + SinhIntegral[ArcSinh[a*x]] - 3*SinhIntegral[3*ArcSinh[a*x]]
)/a^3

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fricas [F]  time = 0.39, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {x^{2}}{\operatorname {arsinh}\left (a x\right )^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/arcsinh(a*x)^2,x, algorithm="fricas")

[Out]

integral(x^2/arcsinh(a*x)^2, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{2}}{\operatorname {arsinh}\left (a x\right )^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/arcsinh(a*x)^2,x, algorithm="giac")

[Out]

integrate(x^2/arcsinh(a*x)^2, x)

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maple [A]  time = 0.14, size = 56, normalized size = 1.04 \[ \frac {\frac {\sqrt {a^{2} x^{2}+1}}{4 \arcsinh \left (a x \right )}-\frac {\Shi \left (\arcsinh \left (a x \right )\right )}{4}-\frac {\cosh \left (3 \arcsinh \left (a x \right )\right )}{4 \arcsinh \left (a x \right )}+\frac {3 \Shi \left (3 \arcsinh \left (a x \right )\right )}{4}}{a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/arcsinh(a*x)^2,x)

[Out]

1/a^3*(1/4/arcsinh(a*x)*(a^2*x^2+1)^(1/2)-1/4*Shi(arcsinh(a*x))-1/4/arcsinh(a*x)*cosh(3*arcsinh(a*x))+3/4*Shi(
3*arcsinh(a*x)))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {a^{3} x^{5} + a x^{3} + {\left (a^{2} x^{4} + x^{2}\right )} \sqrt {a^{2} x^{2} + 1}}{{\left (a^{3} x^{2} + \sqrt {a^{2} x^{2} + 1} a^{2} x + a\right )} \log \left (a x + \sqrt {a^{2} x^{2} + 1}\right )} + \int \frac {3 \, a^{5} x^{6} + 6 \, a^{3} x^{4} + 3 \, a x^{2} + {\left (3 \, a^{3} x^{4} + a x^{2}\right )} {\left (a^{2} x^{2} + 1\right )} + {\left (6 \, a^{4} x^{5} + 7 \, a^{2} x^{3} + 2 \, x\right )} \sqrt {a^{2} x^{2} + 1}}{{\left (a^{5} x^{4} + {\left (a^{2} x^{2} + 1\right )} a^{3} x^{2} + 2 \, a^{3} x^{2} + 2 \, {\left (a^{4} x^{3} + a^{2} x\right )} \sqrt {a^{2} x^{2} + 1} + a\right )} \log \left (a x + \sqrt {a^{2} x^{2} + 1}\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/arcsinh(a*x)^2,x, algorithm="maxima")

[Out]

-(a^3*x^5 + a*x^3 + (a^2*x^4 + x^2)*sqrt(a^2*x^2 + 1))/((a^3*x^2 + sqrt(a^2*x^2 + 1)*a^2*x + a)*log(a*x + sqrt
(a^2*x^2 + 1))) + integrate((3*a^5*x^6 + 6*a^3*x^4 + 3*a*x^2 + (3*a^3*x^4 + a*x^2)*(a^2*x^2 + 1) + (6*a^4*x^5
+ 7*a^2*x^3 + 2*x)*sqrt(a^2*x^2 + 1))/((a^5*x^4 + (a^2*x^2 + 1)*a^3*x^2 + 2*a^3*x^2 + 2*(a^4*x^3 + a^2*x)*sqrt
(a^2*x^2 + 1) + a)*log(a*x + sqrt(a^2*x^2 + 1))), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {x^2}{{\mathrm {asinh}\left (a\,x\right )}^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/asinh(a*x)^2,x)

[Out]

int(x^2/asinh(a*x)^2, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{2}}{\operatorname {asinh}^{2}{\left (a x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2/asinh(a*x)**2,x)

[Out]

Integral(x**2/asinh(a*x)**2, x)

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